3[2-2-4(y-1)]=3(2y+8)

Solution for 3[2-2-4(y-1)]=3(2y+8) equation:

Simplifying
3[2 + -2 + -4(y + -1)] = 3(2y + 8)

Reorder the terms:
3[2 + -2 + -4(-1 + y)] = 3(2y + 8)
3[2 + -2 + (-1 * -4 + y * -4)] = 3(2y + 8)
3[2 + -2 + (4 + -4y)] = 3(2y + 8)

Combine like terms: 2 + -2 = 0
3[0 + 4 + -4y] = 3(2y + 8)
3[4 + -4y] = 3(2y + 8)
[4 * 3 + -4y * 3] = 3(2y + 8)
[12 + -12y] = 3(2y + 8)

Reorder the terms:
12 + -12y = 3(8 + 2y)
12 + -12y = (8 * 3 + 2y * 3)
12 + -12y = (24 + 6y)

Solving
12 + -12y = 24 + 6y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-6y' to each side of the equation.
12 + -12y + -6y = 24 + 6y + -6y

Combine like terms: -12y + -6y = -18y
12 + -18y = 24 + 6y + -6y

Combine like terms: 6y + -6y = 0
12 + -18y = 24 + 0
12 + -18y = 24

Add '-12' to each side of the equation.
12 + -12 + -18y = 24 + -12

Combine like terms: 12 + -12 = 0
0 + -18y = 24 + -12
-18y = 24 + -12

Combine like terms: 24 + -12 = 12
-18y = 12

Divide each side by '-18'.
y = -0.6666666667

Simplifying
y = -0.6666666667